Suppose X and Y Are Continuous Random Variables With Joint Pdf FX Y EXy
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3. Suppose continuous random variables X and Y have joint PDF given by: fxx(z,y) = I52?y if 0<x<1,0<y<1,and ypx and zero otherwise a. (4 points) Find the marginal PDF of X b. (4 points) Suppose the marginal PDF of Y is as given below: Find the CDF of Y: fr(y) = 5y' when 0 < y < 1 and zero otherwise c. (5 points) What is E[Y]? d. (5 points) What is var(Y)?
Related Question
Random variables X and Y are distributed according to the joint PDF @, y) = {0, if 1<x<y < 2 fx,(x, otherwise (1) Are X and Y independent? Justify your answer (2) Find the constant a. (3) Determine the marginal PDF fy(y): (4) Determine the expected value of - 1 given that Y =
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Hi I'm David and I'm here to have your answering your question. Now let me bring up your question here in the question. Well even the champ pdf from the Children um provost accent why? Where we had a parameter? They will be unknown Here. The question one asking us that our X&Y. Independent. The answer for this question here will be no because their support depend on each other. And particularly it will be the one small equal to x smaller echo to wine small equity to therefore they are not independent now to answer the question too. Which is why the constant. I imagine that the the point growth of the density F. X. Y. Our the X. Dy it must be difficult to one. Therefore we can be right this one will be the A. And we do the the X. 1st and dy after We C. X. signals from one gy. And when it goes from 1 to 2. Mhm. So this one we should get together with a constant camping outside from 1-2. The integral inside here can you go to the one man is one And then we have Dy now we have entirely ripped them. The why don't we go to the one square on with you Minors until arrived in the one echoed you y Environment from 1- two. So we have two inside we have the funding only which will be too 212 and then plus minus here. If you put the one inside we're gonna have the one half minus one and then we should get echo to this one will be zero. This will be the one month and a half will be a half. So we've got our two. Therefore we have one. It will echo too. I am too. I would equal to two. Now when I get to kill we should be able to write down the pdf. Can you go to the to if the next model echoed to any small equal to to be greater than one. Now, the next one. Once you file the marginal bdm the Y. So by formula will be the integrated F. X. Y. Over the X. And X. Here we see it goes from one up to the Y. Now we have the truth will be the constant and then attended 50 off that the excuse me the ax environment from going to why They were an echo tuned the two Y -1 For the wine. It goes from the value of the 1-2. And then the number four we have to find expected very under one of the X. Given that one. Could you create a jew? So once you find a after the one of X. Given them the Y. Equal to three and two. Do you find this one? First of all? How to find uh marching against them? The ax Given then the one Echo 2, three and up to. So this one to echo do the john B. D. F. On the X. Given, going to create a jew. The only man F. Under Y given attitude interpret you. So we have a company F. And that one could trade up to it will be equal to the to and then giving that and then dividing by the UAE equity trader joe's. You have the 23 and up to minus one. It will simply find this when we have to cancel. I wanted to 3/2 management will be a half. The values that we're gonna do With the exhale must be between the one opportunity three out of two only. And now we want to find E. R. The one of the X. Even then why it got to the tree under ju if we go to the integral after one of the X. Times the density will be the two. The act Found the ex Girl from 1 203 out of two. So get echo to the to open outside until the rift in the one of the expected to manage one of the X square. Sorry. And I'll tell you everything, I'm just wanting to change that and then I'm absolutely aunt N violated from 1 to to adopt you. So can you go to the two times LM 302 months and then under one. So I get to go to the two and then on the tree on top too. And that's where the answer to discussion here, The # two will be a constant opportunity to and this will be the answer for that one.
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